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A gold wire carries a current of 76.2 mA.

(a) Find the number of electrons that flow past a given point in the wire in 10.4 minutes.
[Answer] electrons

b)In what direction do the electrons travel with respect to the current?
o opposite direction
o same direction
o The magnitude is zero.

Respuesta :

#a

  • Time=10.4min=10.4(60s)=624s
  • Current=76.2mA=76.2×10^{-3}A=I

Now

  • Charge=Q

[tex]\\ \tt\Rrightarrow Q=\dfrac{I}{t}[/tex]

[tex]\\ \tt\Rrightarrow Q=\dfrac{76.2\times 10^{-3}}{624}[/tex]

[tex]\\ \tt\Rrightarrow Q=0.122\times 10^{-3}[/tex]

[tex]\\ \tt\Rrightarrow Q=122\times 10^{-6}C[/tex]

[tex]\\ \tt\Rrightarrow Q=122\mu C[/tex]

#b

  • Same direction

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