Respuesta :
Answer:
6 gallons of 10% ethanol gas and 3 gallons of the E70 fuel.
Step-by-step explanation:
Let the volume of 10% ethanol gas be x gallons and the volume of 70% be y gallons.
The resulting mixture ( 9 gallons) must have a strength of 30% ethanol.
SO WE HAVE THE SYSTEM:
x + y = 9
0.10x + 0.70y = 0.30 * 9
0.10x + 0.70y = 2.7
Multiplying the first equation by -0.10:
-0.10x - 0.10y = -0.9
Adding the last 2 equations:
0 + 0.60y = 1.8
y = 1.8 / 0.6 = 3 gallons.
So x = 9 - 3 = 6 gallons.
Bc you will contain gallons fuel 70 percent use up full even Jin you’re car umm use ethanol free