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Given the equation of a circle. X^2+ y^2 - 6x + 2y +1 = 0, find the coordinates of the center and the length of the radius.
Coordinates for the center=
Length of the radius =

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Answer:

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nfeinglass910
Answer:
Center: (3, -1)
Radius: 3

Steps:
Rewrite in standard form to find the center
(h,k) and radius.

x^2 + y^2 - 6x + 2y + 1 = 0
Standard Form: (x - 3)^2 + (y + 1)^2 = 9

Center: (3, -1)
Radius: 3