kcgriffin2005
contestada

A skydiver was directly above a ferris wheel when he jumped out of the plane. His friend was watching at the landing field and looking up at the airplane at an angle of 50°. The friend’s eyes were 5.5 feet above the ground when looking up, and he was standing 1050 ft from the ferris wheel. How high was the skydiver when he jumped?

Respuesta :

Using the slope concept, it is found that the skydiver has at a height of 1257 ft when he jumped.

What is a slope?

The slope is given by the vertical change divided by the horizontal change, and it's also the tangent of the angle of depression.

In this problem:

  • The vertical change is of x - 5.5, in which x is the skydiver's height.
  • The horizontal change is of 1050 ft.
  • The angle is of 50º.

Hence:

[tex]\tan{50^\circ} = \frac{x - 5.5}{1050}[/tex]

[tex]x - 5.5 = 1.19175359259 \times 1050[/tex]

[tex]x = 1257[/tex]

The skydiver has at a height of 1257 ft when he jumped.

More can be learned about the slope concept at https://brainly.com/question/18090623

Otras preguntas