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At 45.2 L cylinder containing C2H2F4 at a pressure of 3.00 atm is connected by the valve to 4060 mL cylinder containing N2H4 at 1.50 atm pressure. Calculate the partial pressuure(atm) of N2H4 when the valve is opened.

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pstnonsonjoku

The partial pressure of the N2H4 gas  is 1.50 atm.

Dalton's law of partial pressure

From the Dalton's law of partial pressure, the total pressure of a mixture of gases is the sum of the individual partial pressures of all the gases present in the mixture.

We have the following;

C2H2F4  =  3.00 atm

N2H4 = c

Total pressure = 3.00 atm + 1.50 atm = 4.50 atm

Hence, the partial pressure of the N2H4  is N2H4.

Learn more about partial pressure: https://brainly.com/question/14623719

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