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Calculate the efficiency of a 60W lightbulb that emits 2.0W of visible light

Respuesta :

The efficiency of the 60 W light bulb that emits 2 W  of visible light is 3.3%

How to determine efficiency

Efficiency can be obtained according to the following equation:

Efficiency = (power output / power input) × 100

With the above formula, we can obtain the efficiency of the light bulb as follow:

  • Power input = 60 W
  • Power output = 2 W
  • Efficiency =?

Efficiency = (power output / power input) × 100

Efficiency = (2 / 60) × 100

Efficiency = 3.3%

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