The efficiency of the 60 W light bulb that emits 2 W of visible light is 3.3%
Efficiency can be obtained according to the following equation:
Efficiency = (power output / power input) × 100
With the above formula, we can obtain the efficiency of the light bulb as follow:
Efficiency = (power output / power input) × 100
Efficiency = (2 / 60) × 100
Efficiency = 3.3%
Learn more about efficiency:
https://brainly.com/question/2009210