Respuesta :

Answer:

Perimeter of rectangle = 2L + 2W

2L + 2 * 36 = 148

2L = 148 - 72

2L = 76

L = 38 inches

Given :-

  • Width of rectangle = 36 inches
  • Perimeter of rectangle = 148 inches.

[tex] \\ [/tex]

To find:-

  • Length of rectangle

[tex] \\ [/tex]

Solution:-

We know:-

[tex] \bigstar \boxed{ \rm Perimeter \: of \: rectangle = 2(length + width)}[/tex]

[tex] \\ [/tex]

So:-

[tex] \\ [/tex]

[tex] \dashrightarrow \sf 148 = 2(length + 36) \\ [/tex]

[tex] \\[/tex]

[tex] \dashrightarrow \sf 148 = 2(length) + 2(36) \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf 148 = 2(length) + 2 \times 36 \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf 148 = 2(length) + 72 \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf 148 = 2length + 72 \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf 148 - 72= 2length \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf76= 2length \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf 2length = 76 \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf length = \dfrac{76}{2} \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \sf length = \cancel \dfrac{76}{2} \\ [/tex]

[tex] \\ [/tex]

[tex] \dashrightarrow \bf length = 38 \: inches[/tex]