A piece of wire 10 cm long is bent to form a
right-angled triangle.
The two shorter sides have lengths of x cm
and 2x cm respectively.
(a) Form an equation in x and show that it
reduces to x2 - 15x + 25 = 0.
(b) Hence find the length of the longest side.

Respuesta :

a) We can actually use a linear equation for x, given by:

x*(3 + √5) = 10cm

With the solution x = 1.91cm

b) The longest side is:

√5*x = 4.27cm

Finding the sides of a triangle rectangle.

You need to remember the Pythagorean's theorem, it says that the sum of the squares of the two shorter sides on a right triangle is equal to the square of the hypotenuse.

a) Here we know that the two shorter sides have a length:

x and 2x.

Then we have:

x^2 + (2x)^2 = H^2

x^2 + 4*x^2 = H^2

Where H is the hypotenuse, then we can rewrite:

5*x^2 = H^2

(√5)*x = H

Finally, we know that the perimeter of the triangle is 10 cm, then we have:

x + 2x + √5*x = 10cm

x*(1 + 2 + √5) = 10cm

x*(3 + √5) = 10cm

x = (10 cm)/(3 + √5) = 1.91cm

Notice that in this procedure we got a linear equation instead of the quadratic one we would got in point a (but the solution is the same, just a simpler approach.).

b) The length of the longest side is:

√5*x = √5*1.91cm = 4.27cm

If you want to learn more about right triangles, you can read:

https://brainly.com/question/2217700