The midsegment divides the trapezoid into two equal segments
The length of the midsegment is 6.23 units
The vertices are given as:
A(0, 0), B(2, 5), C(3, 5), and D(8, 0)
Start by calculating the lengths of AB and CD using the following distance formula
[tex]d =\sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}[/tex]
So, we have:
[tex]AB =\sqrt{(2 -0)^2 + (5 -0)^2} = \sqrt{29}[/tex]
[tex]CD =\sqrt{(8 -3)^2 + (0 -5)^2} = \sqrt{50}[/tex]
The length of the midsegment is then calculated as:
[tex]L = \frac{1}{2} * (AB + CD)[/tex]
So, we have:
[tex]L = \frac{1}{2} * (\sqrt{29} + \sqrt{50})[/tex]
Add the radicals
[tex]L = \frac{1}{2} * 12.46[/tex]
[tex]L = 6.23[/tex]
Hence, the length of the midsegment is 6.23 units
Read more about midsegments at:
https://brainly.com/question/7423948
