Answer:
-12
Step-by-step explanation:
Apply the radical rule : [tex]\sqrt[n]{-a} =-\sqrt[n]{a}[/tex]
Therefore, [tex]\sqrt[3]{-1728} =-\sqrt[3]{1728}[/tex]
Factorise 1728: [tex]1728=12^3[/tex]
Therefore, [tex]\sqrt[3]{-1728} =-\sqrt[3]{12^3}[/tex]
Apply the radical rule: [tex]\sqrt[n]{a^n} =a, \ \ \ \ a\geq 0[/tex]
Therefore, [tex]-\sqrt[3]{12^3}=-12[/tex]
