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750.0g of water that was just boiled (heated to 100.0/c loses 78.45KJ of heat as it cools.What is the final temperature of water ?

Respuesta :

  • Mass=m=750g=0.75kg
  • Q=78.45\times 10^3J=78450J
  • T_i=100°C
  • T_f=?
  • Specific heat capacity=c=4200J/kg°C

According to thermodynamics

[tex]\\ \tt\bull\rightarrowtail Q=mc\Delta T[/tex]

[tex]\\ \tt\bull\rightarrowtail Q/mc=\Delta T[/tex]

[tex]\\ \tt\bull\rightarrowtail \Delta T=\dfrac{78450}{0.75(4200)}[/tex]

[tex]\\ \tt\bull\rightarrowtail \Delta T=24.9°C[/tex]

[tex]\\ \tt\bull\rightarrowtail T_i-T_f=24.9[/tex]

[tex]\\ \tt\bull\rightarrowtail T_f=100-24.9=76.1°C[/tex]

mahima6824soni

The final temperature of water is 76.1

What do you mean by temperature?

Temperature is the hotness or coldness of any object or body. It is measured in kelvin.

The mass of water is 750 g or 0.75 kg.

Q is 78.45

T is i =100

c (specific heat capacity) is 4200 J/kg

By the formula of

[tex]Q = MC\Delta T\\\\ \dfrac{Q}{MC} = \Delta T\\\\\\\Delta T = \dfrac{78.45}{0.75 \times 4200}\\\\\Delta T = 24.9 \\\\T_i - T_f = 24.9\\\\T_f = 100 - 24.9 = 76.1[/tex]

Thus, the final temperature is 76.1

Learn more about temperature

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