Answer:
[tex]a_n=\frac{3}{7} +\frac{1}{7}n[/tex]
[tex]a_{10}=1\frac{6}{7}[/tex]
Step-by-step explanation:
Notice the pattern, everytime you add 1/7 to the previous answer
According to the term formula, [tex]a_{n}=a_1+(n-1)d[/tex]
[tex]a_n=[/tex] nth term
[tex]a_1=[/tex] First term
d = common difference
To find [tex]a_n[/tex], we have to substitute terms.
We would get: [tex]a_n=\frac{4}{7}+(n-1)\frac{1}{7}=\frac{4}{7}+\frac{1}{7} n-\frac{1}{7}=\frac{3}{7} +\frac{1}{7}n[/tex]
Using [tex]a_n=\frac{3}{7} +\frac{1}{7}n[/tex] and given that n = 10, we can find the answer
[tex]a_{10}=\frac{3}{7} +\frac{10}{7}=\frac{13}{7}=1\frac{6}{7}[/tex]
Hope this helps :)
Have a great day!
