The length of the diagonal of the box is approximately 31 units.
Diagonal of a Box
Diagonal, d, = √(length² + width² + height²)
Given:
RV=29
RS = 21
RT= 24
Thus:
length of the box = ST = ?
Use Pythagorean Theorem to find ST:
ST = √(RT² - RS²)
Substitute
ST = √(24² - 21²)
ST = 12
Height of the box = SV = ?
Use Pythagorean Theorem to find SV:
SV = √(RV² - RS²)
Substitute
SV = √(29² - 21²)
SV = 20
Find the diagonal of the box, RU:
RU = √(ST² + RS² + SV²)
Substitute
RU = √(12² + 21² + 20²)
RU = 31 units.
Therefore, the length of the diagonal of the box is approximately 31 units.
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