Answer:
[tex]h^{-1}[/tex] (x) = 5 - 3x
Step-by-step explanation:
let h(x) = y and rearrange making x the subject
y = - [tex]\frac{1}{3}[/tex] x - [tex]\frac{5}{3}[/tex] ( multiply through by 3 to clear the fractions )
3y = - x - 5 ( add 5 to both sides )
3y + 5 = - x ( multiply through by - 1 )
- 3y - 5 = x
change y back into terms of x with x = [tex]h^{-1}[/tex] (x) , that is
[tex]h^{-1}[/tex] (x) = - 3x - 5
