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When a customer buys a family-sized meal at a certain restaurant, they get to choose 3 side dishes from 9 options. Suppose a customer is going to choose 3 different side dishes.
How many groups of 3 different side dishes are possible?

ANSWER: 84

Respuesta :

reinhard10158

Step-by-step explanation:

9! / (3! × (9-3)!) = 9! / (3! × 6!) = 9×8×7 / (3×2) =

= 3×4×7 = 84

this is a combination of picking 3 items out of possible 9, where the sequence does not matter, and there are no repetitions (3 DIFFERENT side dishes).

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