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A bowling bowl of mass 6.2 kg moves with a velocity of 9.4 m/s. A resistive force of -6.0 N is applied for 2.5 sec. Find the final velocity.

Respuesta :

onyebuchinnaji

The final velocity of the bowling bowl is 6.98 m/s.

Newton's second law of motion

The final velocity of the bowl is calculated by applying Newton's second law of motion as follows;

[tex]F = \frac{m(v-u)}{t} \\\\[/tex]

where;

  • F is the applied on the bowling bowl
  • m is the mass of the bowling bowl
  • v is the final velocity of the bowling bowl
  • u is the initial velocity of the bowling bowl
  • t is the time of motion of the bowling bowl

[tex]m(v-u) = Ft\\\\v-u = \frac{Ft}{m} \\\\v = \frac{Ft}{m} + u\\\\v = \frac{-6 \times 2.5}{6.2} + 9.4\\\\v = 6.98 \ m/s[/tex]

Thus, the final velocity of the bowling bowl after the resistive force was applied is 6.98 m/s.

Learn more about Newton's second law of motion here: https://brainly.com/question/3999427

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