Respuesta :
The reactant that run out first in the reaction is [tex]\rm Fe_2O_3[/tex].
The balanced chemical reaction for welding is:
[tex]\rm Fe_2O_3\;+\;2\;Al\;\rightarrow\;Al_2O_3\;+\;2\;Fe[/tex]
The balanced chemical equation gives the 2 moles of Al reacts with 1 moles of iron oxide.
Computation for limiting reactant
The reactant that exhausts prior in the reaction is known as limiting reactant.
The moles of a sample is given as:
[tex]\rm Moles=\dfrac{Mass}{Molar\;mass}[/tex]
The available moles of iron oxide is:
[tex]\rm Moles\;Fe_2O_3=\dfrac{ 1. 873\;\times\;10^2\;g}{159.69 \;g/mol} \\ Moles\;Fe_2O_3=1.1\;mol[/tex]
The available moles of iron oxide is 1.1 mol
The available moles of Al are:
[tex]\rm Moles\;Al=\dfrac{94. 51\;g}{26.9\;g/mol} \\Moles\;Al=3.5\;mol[/tex]
From the balanced chemical equation, for the reaction with 1 mole iron oxide 2 moles Al is required.
Thus, for the reaction with 1.1 moles Iron oxide, 2.2 moles Al is required.
The available moles of Al is more than the required, therefore, Al is the excess reactant and [tex]\rm Fe_2O_3[/tex] is the limiting reactant.
The reactant that run out first in the reaction is [tex]\rm Fe_2O_3[/tex].
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