A spinner for a board game consists of a cardboard circle with two plastic arrows anchored to its center. The arrows are congruent isosceles triangles connected at their bases, as shown. 2 isosceles triangles are connected at their bases. The length of the base is 2 centimeters. The total perimeter of each triangle is 10 centimeters. Heron’s formula: Area = StartRoot s (s minus a) (s minus b) (s minus c) EndRoot The base of each triangle measures 2 centimeters and the perimeter of each triangle is 10 centimeters. What is the approximate total area of the plastic triangles on the spinner? 3. 9 square centimeters 6. 7 square centimeters 7. 7 square centimeters 13. 4 square centimeters.

Respuesta :

A triangle is isosceles triangle when the two sides and two angle of the triangle in equal in measure.

The approximate total area of the plastic triangles on the spinner is 7.7 squared centimetre.

What is isosceles triangle?

A triangle is isosceles triangle when the two sides and two angle of the triangle in equal in measure.

The area of the isosceles triangle is given as,

[tex]A=\dfrac{1}{2}\times b\times \sqrt{a^2-\dfrac{b^2}{4} }[/tex]

Here, [tex]a[/tex] is the measure of equal sides and [tex]b[/tex] is the measure of third side.

Given information-

The arrows of board game are congruent isosceles triangles connected at their bases.

isosceles triangles are connected at their bases.

The base of each triangle measures 2 centimetres

The perimeter of each triangle is 10 centimetres.

The perimeter of a triangle is sum of all its sides.

As the given triangle is isosceles triangle. Thus both the sides of the triangle should be equal.

Suppose the equal sides is x centimetres. The measure of third side is given which is equal to 2 centimetres. Thus,

[tex]x+x+2=10\\2x=10-2\\2x=8\\x=\dfrac{8}{2} \\x=4[/tex]

Hence the length of the equal sides of the isosceles triangle is 4 cm.

Using the above formula as,

[tex]A=\dfrac{1}{2}\times b\times \sqrt{a^2-\dfrac{b^2}{4} }\\A=\dfrac{1}{2}\times 2\times \sqrt{4^2-\dfrac{2^2}{4} }\\A= \sqrt{16-\dfrac{4}{4} }\\A=3.871[/tex]

Hence the area of one plastic arrow triangle is 3.71 square centimetre. The approximate total area of the plastic triangles on the spinner is twice of it. Thus,

[tex]A=3.71\times2\\A=7.7[/tex]

Thus the approximate total area of the plastic triangles on the spinner is 7.7 squared centimetre.

Learn more about the isosceles triangle here;

https://brainly.com/question/1475130

Answer:

The correct answer would be option C. 7.7 square centimeters

Step-by-step explanation:

Just got it right on edge. :)

Hope this helps!

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