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Consider two simple pendula. Pendulum 1 has a length of L and a bob mass of m. Pendulum 2 has a length of 4L and a bob mass of 4m. If the period of pendulum 1 is 4 seconds, then the period of pendulum 2 is...


2 s
16 s
1 s
8 s

Respuesta :

thishigopal

Answer:

8s

Explanation:

period of pendulum = 2π*√(l/g)

l = length of pendulum

period for 1st pendulum = 4 sec

thats 2π*√(l/g) = 4

for 2nd pendulum

length = 4 l

substitute 4l in formula

2π*√4l/g = 2*4= 8s

Eduard22sly

Given the data from the question, the period of the pendulum 2 is 8 s

Data obtained from the question

  • Length of pendulum 1 (L₁ ) = L
  • Period of pendulum 1 (T₁ ) = 4 s
  • Length of pendulum 2 (L₂) = 4L
  • Period of pendulum 2 (T₂) = ?

How to determine the period of pendulum 2

The period of pendulum 2 can be obtained as illustrated below:

T²₁ / L₁ = T²₂ / L₂

4² / L = T²₂ / 4L

Cancel out L

4² = T²₂ / 4

Cross multiply

T²₂ = 4² × 4

T²₂ = 64

Take the square root of both sides

T₂ = √64

T₂ = 8 s

Learn more about simple pendulum:

https://brainly.com/question/14361236

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