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Consider the following system of equations 2a+3b=23 3a-2b =2 what Is the solution to the system ? Enter the number in each box

Respuesta :

MingYueYue
A = 4 B=5

3a-2b=2
Solve for a= 2(b+1)/3
Solve for b=3a/2

2a+3b=23
Solve for a= 23-3b/2
Solve for b= 23-2a/3

The values of A and B for both equations must be the same.
I worked out A must = 4 and B must = 5

Hope this helps


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