Answer:
→ 12th term of the given AP is -39.
Step-by-step explanation:
Given AP is 16,11,6,1
First term = 16
Common difference =11-16 = -5
We know that
nth term of an AP = an = a+(n-1)d
Now,
12 th term = a12
⇛a12 = a+(12-1)d
⇛a12 = a+11d
⇛a12 = 16+11(-5)
⇛a12 = 16+(-55)
⇛a12 = 16-55
⇛a12 = -39
12th term of the given AP = -39
also read similar questions: a(n)=−6+3(n−1)a, left parenthesis, n, right parenthesis, equals, minus, 6, plus, 3, left parenthesis, n, minus, 1, right parenthesis Find the 16^\text{ th}16 t...
https://brainly.com/question/4692617?referrer
