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a toy rocket is launched from the top of a 48 foot hill. the rockets initial upward velocity is 32 feet per second and its height (h) at any given second (t) is modeled by the equation : h= -16t^2 + 32t +48.
Find the highest point the rocket reaches. show your work

Respuesta :

Answer:

Maximum height is 64 feet

Step-by-step explanation:

For all: h= -16t²+ 32t + 48

1) AOS -> a = -16; b = 32; c = 48

x = -b/2a -> x= -32/(2×-16) = -32/-32 = 32/32 = 1/1 = 1

2) Plug in AOS

h = -16(1)² + 32(1) + 48

h= -16 + 32 + 48

h= 16 + 48

h= 64

Max height is 64