Find the set of values ​​of a for which the point P (2a + 3; 3a-2) is in the fourth quarter of the coordinate plane (with this
Not located on the coordinate axes).

Respuesta :

Answer:

  -3/2 < a < 2/3

Step-by-step explanation:

In the fourth quarter of the coordinate plane, x > 0 and y < 0. This means ...

  2a +3 > 0

  3a -2 < 0

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The first inequality has the solution ...

  2a > -3 . . . . subtract 3

  a > -3/2 . . . . divide by 2

The second inequality has the solution ...

  3a -2 < 0

  3a < 2 . . . . add 2

  a < 2/3 . . . divide by 3

The set of values of 'a' that put P in the fourth quarter is ...

  -3/2 < a < 2/3