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A wooden beam is (3y2 + 7y+1) meters long. If a piece of length (y2 - 10) meters is cut off, express the length of the
remaining piece of beam as a polynomial in y.

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sqdancefan

Answer:

  2y^2 +7y +11

Step-by-step explanation:

The remaining length is the difference between the original and the length cut off:

  remaining = whole length - piece length

  remaining = (3y^2 +7y +1) -(y^2 -10)

  = 3y^2 +7y +1 -y^2 +10  = (3 -1)y^2 +7y +(1 +10)

  remaining = 2y^2 +7y +11

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