The 33rd term of the arithmetic sequence, 7,10,13.... is: 103
Recall:
- An arithmetic sequence has a common difference, d, which is the difference between consecutive terms.
- nth term of an arithmetic sequence is found using: an = a + (n - 1)d, where, a is the first term and d is the common difference.
The sequence, 7,10,13,... is an arithmetic sequence because:
13 - 10 = 10 - 7 = 3
Therefore, to find the 33rd term, substitute a = 7, n = 33, and d = 3 into an = a + (n - 1)d.
[tex]a_{33[/tex] = 7 + (33 - 1)3
[tex]a_{33[/tex] = 7 + (32)3
[tex]a_{33[/tex] = 103.
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