Given that :(1/3)^-2 + (1/4)^-2 = 125^x
⇛[1/(1/3)]²+[1/+1/4)]² = 125^x
Since a^-n = 1/a^n
⇛ (3)²+(4)² = 125^x
⇛ (3×3)+(4×4) = 125^x
⇛ 9+16 = 125^x
⇛25 = 125^x
⇛ 5² =( 5³)^x
⇛ 5² = 5^(3x)
Since (a^m)^n = a^mn
⇛ 2 = 3x
Since the bases are equal then exponents must be equal
⇛3x = 2
⇛ x = 2/3
Therefore,x = 2/3
Answer:- The value of x for the given problem is 2/3.
also read similar questions:- evaluate 1. 5x = 125(x-2) 2. 2(x + 3) = 4 (x + 4)..
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