If 6 hands is 2 feet and 3 feet is 7 arms and 3 arms is 2.5 heads, how many heads is 10 hands? Round to the nearest tenth

Respuesta :

The question is an illustration of unit conversion

10 hands is equivalent to 6.5 heads

The given parameters are:

[tex]\mathbf{6\ hands = 2\ feet}[/tex]

[tex]\mathbf{3\ feet= 7\ arms}[/tex]

[tex]\mathbf{3\ arms= 2.5\ heads}[/tex]

Divide both sides of [tex]\mathbf{6\ hands = 2\ feet}[/tex] by 2

[tex]\mathbf{3\ hands = 1\ feet}[/tex]

Multiply both sides by 3

[tex]\mathbf{3 \times 3\ hands = 3 \times 1\ feet}[/tex]

[tex]\mathbf{9\ hands = 3\ feet}[/tex]

Recall that:

[tex]\mathbf{3\ feet= 7\ arms}[/tex]

Substitute 7 arms for 3 feet

[tex]\mathbf{9\ hands = 7\ arms}[/tex]

Divide both sides by 7

[tex]\mathbf{\frac{9\ hands}{7} = \frac{7\ arms}{7}}[/tex]

[tex]\mathbf{\frac{9\ hands}{7} = 1\ arm}[/tex]

Multiply both sides by 3

[tex]\mathbf{\frac{9\ hands}{7} \times 3= 1\ arm \times 3}[/tex]

[tex]\mathbf{\frac{27\ hands}{7}= 3\ arms}[/tex]

Recall that: [tex]\mathbf{3\ arms= 2.5\ heads}[/tex]

So, we have:

[tex]\mathbf{\frac{27\ hands}{7}= 2.5\ heads}[/tex]

Multiply both sides by 7

[tex]\mathbf{27\ hands= 17.5\ heads}[/tex]

Divide both sides by 27

[tex]\mathbf{1\ hands= \frac{17.5}{27}\ heads}[/tex]

Multiply both sides by 10

[tex]\mathbf{10 \times 1\ hands= 10 \times \frac{17.5}{27}\ heads}[/tex]

[tex]\mathbf{10 \times 1\ hands= \frac{175}{27}\ heads}[/tex]

[tex]\mathbf{10\ hands= \frac{175}{27}\ heads}[/tex]

[tex]\mathbf{10\ hands= 6.5\ heads}[/tex]

Hence, 10 hands is 6.5 heads

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