A motorist accelerates from 0 m/s to 8 m/s in 3 seconds. What is his acceleration? Is this acceleration higher than that of a car which accelerates from 0 to 30 m/s in 6 seconds?

Respuesta :

Answer:

[tex]\boxed {\boxed {\sf \frac {8}{3} \ m/s^2 \ and \ not \ higher \ than \ the \ car's \ acceleration }}[/tex]

Explanation:

Acceleration is the rate of change of velocity with respect to time. It is calculated by dividing the change in velocity by the time.

[tex]a= \frac {v_f-v_i}{t}[/tex]

1. Motorist Acceleration

The motorist accelerates from an initial velocity of 0 meters per second to a final velocity of 8 meters per second in 3 seconds.

  • [tex]v_f[/tex]= 8 m/s
  • [tex]v_i[/tex]= 0 m/s
  • t= 3 s

Substitute the values into the formula.

[tex]a= \frac{ 8 \ m/s - 0 \ m/s }{3 \ s}[/tex]

Solve the numerator.

[tex]a= \frac{8 \ m/s}{3 \ s}[/tex]

[tex]a= \frac{8}{3} \ m/s^2[/tex]

[tex]a \approx 2.667 \m/s^2[/tex]

2. Car Acceleration

The car accelerates from an initial velocity of 0 meters per second to a final velocity of 30 meters per second in 6 seconds.

  • [tex]v_f[/tex]= 30 m/s
  • [tex]v_i[/tex]= 0 m/s
  • t=6 s

Substitute the values into the formula.

[tex]a= \frac{ 30 \ m/s - 0 \ m/s }{6 \ s}[/tex]

Solve the numerator.

[tex]a= \frac{30 \ m/s}{6 \ s}[/tex]

[tex]a= { 5 \ m/s^2}[/tex]

The motorist's acceleration is 8/3 or approximately 2.667 meters per second squared. This is not higher than the car's acceleration of 5 meters per second squared.