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A constant horizontal force of 30.0 N is exerted by a string attached to a 5.0 kg block being pulled across a tabletop. The block also experiences a frictional force of 5.0 N due to contact with the table. What is the horizontal acceleration of the block?​

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joshimahesh30243

Answer:

A 5.00- kg block is placed on top of a 10.0 -kg block (Fig. P5.68). A horizontal force of 45.0 N is applied to the 10.0-kg block, and the 5.00- kg block is tied to the wall. The coefficient of kinetic friction between all surfaces is 0.200. (a) Draw a free-body diagram for each block and identify the action-reaction forces between the blocks.

(b) Determine the tension in the string and the magnitude of the acceleration of the 10.0-kg block.

asuwafohjames

 

The horizontal acceleration of the block is 5 m/s².

To calculate the horizontal acceleration on the block, we use the formula below.

Formula:

  • ma = (F-F')............... Equation 1

Where:

  • m = mass of the block
  • a =  Horizontal acceleration of the block
  • F = Horizontal force exerted on the string
  • F' = Frictional force

Make "a" the subject of the equation.

  • a = (F-F')/m............... Equation 2

Substitute these values into equation 2

  • F = 30 N
  • F' = 5 N
  • m = 5.0 kg

Substitute these values into equation 2

  • a = (30-5)/5
  • a = 25/5
  • a = 5 m/s²

Hence the horizontal acceleration of the block is 5 m/s².

Learn more about horizontal acceleration here: https://brainly.com/question/929566

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