The dimension of the shape is approximately 1.45 meters by 0.55 meters
Assume the shape is a rectangle, that has the following dimensions.
Length = x
Width = y
So, the area is:
Area = xy
The perimeter is
Perimeter = 2(x + y)
Substitute known values
[tex]\mathbf{xy = 0.8m^2}[/tex]
[tex]\mathbf{2(x+y) = 400cm}[/tex]
Express cm as m
[tex]\mathbf{2(x+y) = 4m}[/tex]
Divide through by 2
[tex]\mathbf{x+y = 2m}[/tex]
Make x the subject (ignore the units)
[tex]\mathbf{x= 2 - y}[/tex]
Substitute 2-y for x in [tex]\mathbf{xy = 0.8m^2}[/tex]
[tex]\mathbf{(2-y)y = 0.8}[/tex]
Open brackets
[tex]\mathbf{2y-y^2 = 0.8}[/tex]
Rewrite as:
[tex]\mathbf{y^2 - 2y + 0.8 = 0}[/tex]
Using a calculator, we have:
[tex]\mathbf{y \approx (0.55,1.45)}[/tex]
Recall that:
[tex]\mathbf{x= 2 - y}[/tex]
So, we have:
[tex]\mathbf{x \approx (2-0.55,2-1.45)}[/tex]
[tex]\mathbf{x \approx (1.45,0.55)}[/tex]
Hence, the dimension of the shape is approximately 1.45 meters by 0.55 meters
Read more about areas and perimeters at:
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