In the experiment for determining the empirical formula of magnesium oxide, a student find the masses of empty crucible and crucible+Mg are 25.559 and 26.127, respectively, how many moles Mg are used for the experiment. (round to the thousandth decimal place)

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Abdulazeez10 Abdulazeez10 · Answer 1 · 2021-11-12T17:33:51+01:00

The number of moles of Mg used for the experiment is 0.02337 mole

From the question,

We are to determine the number of moles of Magnesium (Mg) used for the experiment

From the given information,

Mass of empty crucible = 25.559

and

Mass of crucible + Mg = 26.127

First, we will determine the mass of Mg

Mass of Mg = (Mass of crucible + Mg) - (Mass of empty crucible)

Mass of Mg = 26.127 - 25.559

Mass of Mg = 0.568

Now, for the number of moles of Mg used for the experiment,

Using the formula

[tex]Number\ of\ moles = \frac{Mass}{Atomic\ mass}[/tex]

Atomic mass of Mg = 24.305 g/mol

∴ Number of moles of Mg used for the experiment = [tex]\frac{0.568}{24.305}[/tex]

Number of moles of Mg used for the experiment = 0.02337 mole

Hence, the number of moles of Mg used for the experiment is 0.02337 mole

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