Answer:
height ≈ 178.3 m
Step-by-step explanation:
∠ ACB = 27° ( alternate angles )
Using the tangent ratio in the right triangle
tan27° = [tex]\frac{opposite}{adjacent}[/tex] = [tex]\frac{AB}{BC}[/tex] = [tex]\frac{AB}{350}[/tex] ( multiply both sides by 350 )
350 × tan27° = AB , then
AB ≈ 178.3 ( to 1 dec. place )
The height of the plane is approximately 178.3 m
