For a car with standard tires stopping on dry asphalt, its speed S (in mph) can be found from the length of its skid marks according to S = 9.4L0.37 where L is the length (in feet) of the skid marks. Find the error and the relative error in the speed for the skid-mark length if the error in measuring the length is ±10 feet.† (Round your answers to two decimal places.) 200 feet

Respuesta :

The relative error of the speed is the ratio of the absolute error and the actual length

The absolute error and the relative error are 1.24 and 0.62%,

The given parameters are:

[tex]\mathbf{S = 9.4L^{0.37}}[/tex]

[tex]\mathbf{L = 200 \pm 10}[/tex]

Start by calculating the absolute error:

Differentiate [tex]\mathbf{S = 9.4L^{0.37}}[/tex]

[tex]\mathbf{S'= 0.37 \times 9.4L^{-0.63} L'}[/tex]

So, we have:

[tex]\mathbf{S'= 0.37 \times 9.4 \times 200^{-0.63} \times 10}[/tex]

[tex]\mathbf{S'= 1.24}[/tex]

So, the relative error is:

[tex]\mathbf{R = \frac{S'}{L} \times 100\%}[/tex]

This gives

[tex]\mathbf{R = \frac{1.24}{200} \times 100\%}[/tex]

[tex]\mathbf{R = \frac{124\%}{200} }[/tex]

[tex]\mathbf{R = 0.62\% }[/tex]

Hence, the absolute error and the relative error are 1.24 and 0.62%, respectively.

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