Answer: [tex](x-2)^2 + (y+3)^2 = 36\\\\[/tex]
Work Shown:
[tex](x-h)^2 + (y-k)^2 = r^2\\\\(x-2)^2 + (y-(-3))^2 = 6^2\\\\(x-2)^2 + (y+3)^2 = 36\\\\[/tex]
Note that (h,k) = (2,-3) is the center and r = 6 is the radius. The last line is not expanded out using the FOIL rule because its common practice to leave it in [tex](x-h)^2 + (y-k)^2 = r^2\\\\[/tex] form. This form allows the reader to quickly determine the center and radius (rather than have to do a lot of algebraic steps before hand).
