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What is the concentration of glucose (C6H12O6, MM=180.16 g/mol) solution that was prepared by dissolving 50.500 g of glucose in 500.0 mL of solution? Assume the solution has a density of 1.00 g/mL.

Find the following:

A. %(m/m)

B. M
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Formulae:

- %(m/m)= (mass of solute/mass of solution) x 100%

-M (molarity) = moles of solute/L of solution

Respuesta :

Answer:

0.56 M

10.1 %m/m

Explanation:

What is the concentration of glucose (C6H12O6, MM=180.16 g/mol) solution that was prepared by dissolving 50.500 g of glucose in 500.0 mL of solution? Assume the solution has a density of 1.00 g/mL.

50.500 g/ 180.16 = 0.280 mol

es

distibuted over 0.500 L gives a concentration of

0.280/0.500 L=0.56 moles/L = 0.56 M

500 ml H2O = 500 g

m/m =50.500/500= 0.101 = 10.1 %m/m

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