Answer:
0.08 M
Explanation:
here...
1. water and a salt
2. Magnesium hydroxide reacts with HCl to produce a solution that is neutral.
3. titrant
4. 0.08 M
5. indicator
{quizlet: captncrun}
The concentration of sodium hydroxide is 0.08 M. The correct option is the second option 0.08 M
From the question,
We are to determine the concentration of sodium hydroxide
The given reaction is
HCl + NaOH → NaCl + H₂O
This means
1 mole of HCl is required to completely neutralize 1 mole of NaOH
To determine the concentration of sodium hydroxide,
We will use the formula
[tex]\frac{C_{A}V_{A} }{C_{B}V_{B}} = \frac{n_{A}}{n_{B}}[/tex]
Where
[tex]C_{A}[/tex] is the concentration of acid
[tex]C_{B}[/tex] is the concentration of base
[tex]V_{A}[/tex] is the volume of acid
[tex]V_{B}[/tex] is the volume of base
[tex]n_{A}[/tex] is the mole ratio of acid
[tex]n_{B}[/tex] is the mole ratio of base
From the give information
[tex]C_{A} = 0.10 \ M[/tex]
[tex]V_{A} = 40 \ mL[/tex]
[tex]V_{B} = 50 \ mL[/tex]
From the balanced chemical equation
[tex]n_{A} = 1[/tex]
[tex]n_{B} = 1[/tex]
Putting the above parameters into the formula, we get
[tex]\frac{0.10 \times 40}{C_{B} \times 50} = \frac{1}{1}[/tex]
Then
[tex]C_{B} \times 50 = 0.10 \times 40[/tex]
∴ [tex]C_{B}=\frac{0.1 \times 40}{50}[/tex]
[tex]C_{B}=\frac{4}{50}[/tex]
[tex]C_{B}=0.08[/tex]
Hence, the concentration of sodium hydroxide is 0.08 M. The correct option is the second option 0.08 M
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