PLS help


C is the circumcenter of isosceles triangle ABD with vertex angle ∠ABD. Does the following proof correctly justify that triangles ABE and DBE are congruent?


It is given that triangle ABD is an isosceles triangle, so segments AB and DB are congruent by the definition of isosceles triangle.
It is given that C is the circumcenter of triangle ABD, making segment BE a median.
By the definition of perpendicular, angles AEB and DEB are 90°, so triangles ABE and DEB are right triangles.
Triangles ABE and DEB share side BE making it congruent to itself by the reflexive property.
Triangles ABE and DBE are congruent by HL.


There is an error in line 1; segments AB and BD are given to be congruent.
There is an error in line 2; segment BE should be a perpendicular bisector.
There is an error in line 4; segment BE is not a shared side.
The proof is correct.

PLS help C is the circumcenter of isosceles triangle ABD with vertex angle ABD Does the following proof correctly justify that triangles ABE and DBE are congrue class=

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Answer:

There is an error in line 2; segment BE should be a perpendicular bisector.

Step-by-step explanation:

I took the test, i got it right. :)

The correct option is [tex]\bold{2^{nd}}[/tex] i.e. there is an error in line 2 segment BE should be a perpendicular bisector.

Given: C is the circumcentre of isosceles triangle ABD with vertex angle ∠ABD  and proof is given.

Thus, choose the correct option by following proof correctly justify that triangles ABE and DBE are congruent and the proof is,

Proof: It is given that triangle ABD is an isosceles triangle, so segments AB and DB are congruent by the definition of isosceles triangle.

It is given that C is the circumcenter of triangle ABD, making segment BE a median.

By the definition of perpendicular, angles AEB and DEB are 90°, so triangles ABE and DEB are right triangles.

Triangles ΔABE and ΔDEB share side BE making it congruent to itself by the reflexive property.

Triangles ΔABE and ΔDBE are congruent by HL.

Hence,correct  option is  [tex]\bold{2^{nd}}[/tex]  i.e. there is an error in line 2 segment BE should be a perpendicular bisector.

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