The moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².
The given parameters;
The moment of inertial of the wheel is calculated as follows;
[tex]I = I_{hoop} + 3I_{spoke}\\\\I = MR^2\ + \ 3(\frac{1}{3} mL^2)\\\\I = (4.3 \times 0.67^2) \ + \ (0.15 \times 0.67^2)\\\\I = 2.0 \ kgm^2[/tex]
Thus, the moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².
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find the moment of inertial of the wheel about an axis through its center and perpendicular to the plane of the wheel.
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