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A second 0.69 bullfrog is on a log tilted 26 degrees above horizontal. How large is the normal force of the log on this bullfrog?

Respuesta :

Answer:

Below

Explanation:

To find the normal force of the frog on the inclined plane we can use this formula :

     [tex]Fn = mgCos\alpha[/tex]

     [tex]Fn = (0.69kg)(9.8)Cos(26) \\ = 6.762 Cos(26) \\ = 6.07764 N \\ = 6.08 N[/tex]

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