1. A baseball is thrown vertically into the air with a speed of 24.7 m/s.
a. How high does it go?
b. How long does the round trip up and down require?

Respuesta :

The distance that it travels up is 31.12 m. The time taken for the round trip up and down is 5 seconds.

We can use the formula;

v^2 = u^2 + 2gh

Since the motion is upwards that the acceleration due to gravity has a negative sign so, v^2 = u^2 - 2gh.

Note that, at the maximum height, v =0 m/s so,

u^2 = 2gh

u =  24.7 m/s

g = 9.8 m/s^2

h = u^2/2g

h = ( 24.7 m/s)^2/2 × 9.8 m/s^2

h = 31.12 m

From;

v = u - gt

Since v = 0 at maximum height;

u = gt

t = u/g

t = 24.7 m/s/9.8 m/s^2

t = 2.5

The time taken to go up is the same time taken to come down;

t = 2 × 2.5 = 5 secs

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