This question involves the concepts of the rectangular components of the vector and the resultant of the vectors.
The magnitude of the resultant force is "72.11 N", and it makes an angle of "33.7°" from one of the vectors.
The rectangular components of a vector are those components that have a right angle between them. The resultant of two rectangular components of a vector can be found using the following formula:
[tex]F = \sqrt{F_1^2+F_2^2}[/tex]
where,
F = resultant force = ?
F₁ = First component of force = 40 N
F₂ = Second component of force = 60 N
Correction: The unit in question is given as m/s, while the unit of force is N. Hence, N is taken here.
Therefore,
[tex]F = \sqrt{(40\ N)^2+(60\ N)^2}[/tex]
F = 72.11 N
The following formula can be used to find the angle of resultant from 60N vector:
[tex]\theta = tan^{-1}(\frac{40\ N}{60\ N})\\\\[/tex]
θ = 33.7°
Learn more about rectangular components of a vector here:
https://brainly.com/question/14793638?referrer=searchResults
The attached picture shows the resultant calculation for the rectangular components of a vector.
