- Distance=s=4.3m
- Initial velocity=u=5.6m/s
- Final velocity=v=0
- Acceleration=a
- time=t
[tex]\\ \sf\longmapsto a=\dfrac{v^2-u^2}{2s}[/tex]
[tex]\\ \sf\longmapsto a=\dfrac{-(5.6)^2}{2(4.3)}[/tex]
[tex]\\ \sf\longmapsto a=\dfrac{-31.36}{8.6}[/tex]
[tex]\\ \sf\longmapsto a=-3.6m/s^2[/tex]
And
[tex]\\ \sf\longmapsto v=u+at[/tex]
[tex]\\ \sf\longmapsto t=\dfrac{v-u}{a}[/tex]
[tex]\\ \sf\longmapsto t=\dfrac{-5.6}{-3.6}[/tex]
[tex]\\ \sf\longmapsto t=1.5s[/tex]
