contestada

A fisherman notices that wave crests pass the bow of his anchored boat every 3.0 s. He measures the distance between two crests to be 7.0 m. How fast are the waves traveling?

Respuesta :

jerrybusiness05

Answer:

The time period is

T

=

3.0

s

.

The distance between two crests is

λ

=

8.0

m

.

The frequency of wave can be calculated as,

f

=

1

T

f

=

1

3.0

s

f

=

1

3

s

−

1

The speed of wave can be calculated as,

v

=

f

λ

v

=

(

1

3

s

−

1

)

(

8

m

)

v

=

2.67

m

/

s

Otras preguntas