The given highest power of x in the given function, y = 4·x + 2, is 1,
therefore, the graph of the function is a straight line.
The statement that correctly compares the function shown on the graph
with the function; y = 4·x + 2 is; C. The function shown on the graph has a
smaller rate of change but a higher starting point.
Reasons:
The given function is; y = 4·x + 2
Comparing with the equation for a straight line; y = m·x + c, we have;
The rate of change or slope, m = 4
The y-intercept, starting point, c = 2
Two points on the function shown on the graph are; (0, 4), and (-2, -2)
The slope of the given graph is therefore;
[tex]m = \dfrac{4 - (-2)}{0 - (-2) } = \dfrac{6}{2} = 3[/tex]
The rate of change of the graph, m = 3
The equation of the graph is therefore;
y - 4 = 3·(x - 0)
Which gives;
y = 3·x + 4
The y-intercept, starting point of the graph, is therefore, c = 4
Which gives;
The function shown on the graph has a higher starting point but a smaller rate of change than the given function.
Learn more here:
https://brainly.com/question/18194679
