Respuesta :

Lampa20
First we write equation for circle that consist coordinates of the center and it consists radius. Equation goes like this:

(x-x1)^2 + (y-y1)^2 = r^2

x1 and y1 are coordinates of the center. since the circle's center is at coordinate start that means that (x1,y1) = (0,0)

that means that 64 on the right side of given equation is r^2
r^2 = 64
r = 8

Answer is 8

Answer:

Radius of the circle is 8

Step-by-step explanation:

The equation of a circle is given by

[tex]r^2 = (x -h)^2 + (y-k)^2\\y, k = 0 \\[/tex]  when the cordinate of the circle lies at the center

Thus, the equation of circle becomes

[tex]r^2 = x^2 + y^2\\[/tex]

Where,

r is the radius of the circle

Substituting the given values in above equation, we get -

[tex]r^2 = 64\\r = \sqrt{64} \\r = 8\\[/tex]

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