Respuesta :

arthurpdc
In y-intercept: [tex]x=0[/tex]. Hence:

[tex]3y+4\cdot0=15\iff 3y=15\iff \boxed{y=5}[/tex]

The intersection is the point [tex]P(0,5)\Longrightarrow \boxed{\boxed{A}}[/tex]
bcalle
To find the y intercept of an equation plug zero in for the x's and solve for y. Remember if it is a y intercept, the x value is zero.
3y + 4(0) = 15 
3y = 15
y = 5  (0,5)

Otras preguntas