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In the image, point A marks the center of the circle. Which two lengths must form a ratio of 2:1?
a. HI:EF
b. EF:AD
c. AD:AH
d. AH:HI
e. BC:HI

In the image point A marks the center of the circle Which two lengths must form a ratio of 21 a HIEF b EFAD c ADAH d AHHI e BCHI class=

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Answer:

option b. [tex]EF:AD=2:1[/tex]

Step-by-step explanation:

we know that

In a circle the ratio of the diameter to the radius is equal to [tex]2:1[/tex]

because

[tex]D=2r[/tex]

[tex]2r/r=2:1[/tex]

so

In this problem

EF is a diameter

AD is a radius

therefore

[tex]EF:AD=2:1[/tex]

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