Respuesta :

(1 / cot²θ) + secθ cosθ 


(1 / cot
θ) == tanθ

Therefore

tan²θ + secθ cosθ


secθ == (1 / cos θ)

Therefore

tan²θ + (1 / cosθ) cosθ


The cosθ 's cancel out

Therefore

tan²θ + 1


tan²θ + 1 == sec²θ

Therefore

sec²θ is the simplified answer