0.238g of carbon were burned in the presence of oxygen, the resulting mass was
0.872g. What is the empirical formula?

Respuesta :

Answer:

CO2

Explanation:

We know that C is 0.238g, we have to find what O mass is first so we subtract the result mass from the C mass:

0.872g-0.238g= 0.634g

Now divide the Elements mass by their Molar Mass C is 12.01g/mol and O is 16.00g/mol

C=0.238g / 12.01g/mol= 0.0198mol (g cancels out)

O= 0.634g / 16.00g/mol= 0.0396mol (g cancels out)

The answers we got have to be whole numbers so you have to divide by the smallest mole which is C 0.0198mol

C= 0.0198/0.0198= 1 Carbon

O=0.0396/0.0198=2 Oxygen

CO2