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Rays DA and DC are perpendicular. Point B lies in the interior of ∠ADC. If m∠ADB=(3a+10)° and m∠BDC=13a°, find a, m∠ADB, and m∠BDC.

Respuesta :

abidemiokin

The measures of m∠ADB, and m∠BDC are both 13degrees

If point B lies in the interior of ∠AD and Rays DA and DC are perpendicular C, hence;

  • m∠ADB = m∠BDC
  • m∠ADB + m∠BDC = ∠ADC

Given the following parameters

m∠ADB=(3a+10)°

m∠BDC=13a°

Substitute into the expression

3a + 10 = 13a

3a - 13a = -10

-10a = -10

a = 10/10

a = 1

Get the measure of  m∠ADB

m∠ADB = 3a + 10

m∠ADB = 3(1) + 10

m∠ADB = 13 degrees

Get the measure of  m∠BDC

m∠BDC = 13a

m∠BDC = 13(1)

m∠BDC = 13 degrees

Hence the measure of m∠ADB, and m∠BDC are both 13degrees.

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